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12 comentarios:
Datos:
x = 2,04 km = 2040 m
v = 330 m/s
Aplicando:
v = x/t Þ t = x/v
t = (2040 m)/(330 m/s) Þ t = 6,18 s
2,04 km = 2040 m
S=V.T
2040=330.T
T=2040/330=6,18 segundos
2.04Km=2040m
S=V/T T=S/V
T=2040/330=6.18S
2,04 Km = 2040 m
S = V*T
T = 2040/330=6,18s
2.04 x 1000=2040 pasar a metros
S=V.T, T=S/V
T=2040/330=6.18seg
330ms/s
<-----------
POLICIA DISPARO
<----------->
2,04KM
2,04km--->2040m
S=V.T
2040m=330m/s.t
t=2040m/330m.s=6,18m/s
2,04 km = 2040 m
s=v.t
2040=330.t
t=2040/330=6,18 seg.
x= 2,04 km = 2040 m
v=330 m/s
t= 2040/330= 6,18
330
d ------------------------p
x=2.04=2040
v=330
x=2040.v=330=6.18
x=2,04km-->2040 m
v=330 m/s
t=x/v
t=(2040m)/(330m/s)=6,18 s
el tiempo sera:
2,04km=2040m
2040=330·t
t=2040:330=6,1818...s
S=V.T; 2040=330t; t=2040/330; t=6,18s
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